Sorry for this trivial question. But I'd like to know why this happens^^
Below are results from ADF tests in eviews.
Upper one: I myself estimated ADF equation.
Lower one: Result from the built-in ADF test in Eviews.
Everything is the same except for the value of the contant.
Upper one: the constant is 0.048948
Lower one: the constant is 0.070604
Anybody can explain how this occured?
Thank you in advance.
--------------------------------
Dependent Variable: D(LRGDP)
Method: Least Squares
Date: 10/07/12 Time: 18:02
Sample: 1960Q4 2002Q1
Included observations: 166
Variable Coefficient Std. Error t-Statistic Prob.
LRGDP(-1) -0.064894 0.019120 -3.394079 0.0009
D(LRGDP(-1)) 0.240728 0.075082 3.206210 0.0016
D(LRGDP(-2)) 0.204157 0.075419 2.706967 0.0075
C 0.048948 0.012549 3.900502 0.0001
@TREND 0.000504 0.000153 3.285528 0.0012
R-squared 0.175503 Mean dependent var 0.008316
Adjusted R-squared 0.155018 S.D. dependent var 0.008784
S.E. of regression 0.008074 Akaike info criterion -6.770603
Sum squared resid 0.010496 Schwarz criterion -6.676868
Log likelihood 566.9600 Hannan-Quinn criter. -6.732555
F-statistic 8.567631 Durbin-Watson stat 1.988653
Prob(F-statistic) 0.000003
----------------------------------------------
Augmented Dickey-Fuller Test Equation
Dependent Variable: D(LRGDP)
Method: Least Squares
Date: 10/07/12 Time: 17:49
Sample: 1960Q4 2002Q1
Included observations: 166
Variable Coefficient Std. Error t-Statistic Prob.
LRGDP(-1) -0.064894 0.019120 -3.394079 0.0009
D(LRGDP(-1)) 0.240728 0.075082 3.206210 0.0016
D(LRGDP(-2)) 0.204157 0.075419 2.706967 0.0075
C 0.070604 0.019018 3.712564 0.0003
@TREND(1960Q4) 0.000504 0.000153 3.285528 0.0012
R-squared 0.175503 Mean dependent var 0.008316
Adjusted R-squared 0.155018 S.D. dependent var 0.008784
S.E. of regression 0.008074 Akaike info criterion -6.770603
Sum squared resid 0.010496 Schwarz criterion -6.676868
Log likelihood 566.9600 Hannan-Quinn criter. -6.732555
F-statistic 8.567631 Durbin-Watson stat 1.988653
Prob(F-statistic) 0.000003
Different numbers in ADF test
Moderators: EViews Gareth, EViews Moderator
-
EViews Gareth
- Fe ddaethom, fe welon, fe amcangyfrifon
- Posts: 13605
- Joined: Tue Sep 16, 2008 5:38 pm
Re: Different numbers in ADF test
I cannot replicate what you are seeing. I just did it a number of times on random data, and always achieved matching results.
Code: Select all
create m 1990 2020
series lrgdp = rnd*100
equation eq1.ls d(lrgdp) lrgdp(-1) d(lrgdp(-1)) d(lrgdp(-2)) c @trend
freeze(mytab) lrgdp.uroot(trend,2)
show eq1
show mytab
-
Luv_eviews
- Posts: 2
- Joined: Sun Oct 07, 2012 2:12 am
Re: Different numbers in ADF test
I'm using Eviews7, Gareth.
And you are right. I did the same thing you did. As you posted, they were perfect match.
Below is what I did. And I attached a screenshot.
The range of lrgdp data is from 1947q1 to 2008q2.
I set the sample period from 1960q4 to 2002q1.
1. Using built-in ADF test
Open 'lrgdp' and view-unitroot test-ADF(level, trend and intercept, lag length 2)
2. Estimating ADF test
Quick-Equation estimation
Set sample from 1960q4 2002q1
Specification: d(lrgdp) lrgdp(-1) d(lrgdp(-1)) d(lrgdp(-2)) c @trend
And you are right. I did the same thing you did. As you posted, they were perfect match.
Below is what I did. And I attached a screenshot.
The range of lrgdp data is from 1947q1 to 2008q2.
I set the sample period from 1960q4 to 2002q1.
1. Using built-in ADF test
Open 'lrgdp' and view-unitroot test-ADF(level, trend and intercept, lag length 2)
2. Estimating ADF test
Quick-Equation estimation
Set sample from 1960q4 2002q1
Specification: d(lrgdp) lrgdp(-1) d(lrgdp(-1)) d(lrgdp(-2)) c @trend
- Attachments
-
- Screentshot
- ADF.jpg (235.62 KiB) Viewed 2797 times
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