In http://forums.eviews.com/viewtopic.php?f=7&t=465 Gareth explained the difference between "LS Y C AR(1)" and "LS Y C Y(-1)" estimates.
I have an analogous question about MA estimation.
Assume we have white noise E and MA(1)-process Y generated by Y=C*E(-1)+E with some constant C.
Why the following regressions
LS Y E(-1)
LS Y MA(1)
give different results?
The first one estimates C, while the second one estimates 1/C...
Thanks.
MA estimation
Moderators: EViews Gareth, EViews Moderator
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EViews Gareth
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Re: MA estimation
I'm not sure I follow. E is not observered, so how can regression 1 be calculated?
Re: MA estimation
I assume that E is given. Say,
Then the estimated coefficient at MA(1) is -1/3, while the estimated coefficient at E(-1) is -3.
Code: Select all
series E=nrnd
smpl @first @first+1
series Y=0
smpl @first+1 @last
series Y=E-3*E(-1)
smpl @all
equation ma.ls Y MA(1)
equation ma1.ls Y E(-1)-
startz
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Re: MA estimation
If I remember correctly, an MA coefficient of 1/3 and 3 imply the same correlogram. Choosing the coefficient under 1.0 is just a convention.
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EViews Gareth
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Re: MA estimation
They're two completely different models. The MA model has no knowledge about the E series. It does not assume that E is given. Which is why you will never see identical results.
See what happens when you set the MA coefficient to an absolute value <1.
Edit: Startz beat me to it.
See what happens when you set the MA coefficient to an absolute value <1.
Edit: Startz beat me to it.
Re: MA estimation
startz, Gareth, could you explain this, please. May be some reference.
Does EViews among different representaions with the same correlogram choose invertible one?
Does EViews among different representaions with the same correlogram choose invertible one?
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