Reverse @elem(series, date)

[fmgoto]

Sorry to bother again, but how do I get the i-th element from a date series without fixing? I need to get a given element of a series and paste it at a given element of another series.

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series y = something series y_sa = another_thing y("2010m05") = @elem(y_sa, "2010m05")

But the thing is that I cannot erase the past or future in y.

Any thoughts? Thanks!

[EViews Gareth]

Maybe I'm missing something, but don't you just mean:

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smpl 2010m5 2010m5 y = ysa smpl @all

[fmgoto]

Sorry I did not make myself clear.

I need to add iteratively only the last element to the y series from the y_sa, preserving the previous ones in y.

The solution I have reached so far is to define i = 2010m05 and set y(i) = @elem(y_sa, "2010m05"). I wonder if Eviews would understand y(2010m05) = @elem(y_sa, "2010m05"), instead of i = 2010m05 + y(i) =@elem(y_sa, "2010m05").

Thanks!

[EViews Gareth]

I'm still not clear on why my above solution doesn't do what you want.

[fmgoto]

Because I may need lags and leads, such as y(2010m01) = y_sa(2010m03). Thanks.

[EViews Gareth]

The easiest way to do that is still with samples:

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smpl 2010m1 2010m1 y = y_sa(2) smpl @all

or (not sure if this works, but should):

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smpl 2010m1 2010m1 y = @elem(y_sa,"2010m03") smpl @all

If that doesn't work, you can break it up into two steps:

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smpl 2010m1 2010m1 !val = @elem(y_sa,"2010m03") y = !val smpl @all

[fmgoto]

That last code is great! Didnt think of that. Plain and simple.

The problem here was that there is no mapping from the string "2010m05" to the "i"-th observation of a y series!

Thanks a lot!