EViews.com

Posted: **Thu Feb 09, 2023 8:41 am**

Good morning!
I'm trying to determine capture the right most character from a temporary string, that is a list of the members of a group. However, the code either crashes with a syntax error if I put brackets around the code name as below

Code: Select all


group g_max hsddcus_*
%max = g_max.@members
%max = @replace(%max,"_"," ")
%test = @right({%max},1)

or returns nothing, if I do not use brackets, as below

Code: Select all

group g_max hsddcus_*
%max = g_max.@members
%max = @replace(%max,"_"," ")
%test = @right(%max,1)

Any thoughts on what I'm doing wrong?
As always thank you very much! The fantastic help and customer support is greatly appreciated!
Bob

Posted: **Thu Feb 09, 2023 8:59 am**

The @right function requires the first argument to be a string, so using {%max} is wrong.
The second syntax (without the {}) is correct.

The reason that you end up with an empty string is that the last character of %max is a space. If you add an @trim to the program it should work.

Code: Select all


group g_max hsddcus_*
%max = g_max.@members
%max = @replace(%max,"_"," ")
%max = @trim(%max)
%test = @right(%max,1)

Posted: **Thu Feb 09, 2023 9:16 am**

Thank you sir!

EViews.com

@right error

@right error

Re: @right error

Re: @right error