Interpretation of coefficients: d(lnY)=c+b*(lnX)+e*d(lnZ)

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SEbert
Posts: 6
Joined: Fri May 29, 2015 1:22 am

Interpretation of coefficients: d(lnY)=c+b*(lnX)+e*d(lnZ)

Postby SEbert » Sat Jul 04, 2015 6:48 am

Dear all,

what is the proper interpretation of coefficients in time series regression when using first differencing on logs of the DV and in certain IVs. The log transformation was chosen to aim at elasticities. Differencing was chosen to achieve stationarity.

As d(lnY) [first difference formulation of log in Eviews] can be understood as e.g "growth rate", I now wonder if the elasticity notation holds in this case: e.g. that a 1% change of X leads to a b% change in d(lnY)?

Does this further apply to coefficients of differenced logs of IVs, e.g. given by e*d(lnZ) term, which could be "inflation"? Then, a 1% change in Z leads to a e% change of d(lnY)?

Thank you so much for clarification!

Best,
Sebastian

cyp74
Posts: 16
Joined: Tue Mar 13, 2012 4:47 pm

Re: Interpretation of coefficients: d(lnY)=c+b*(lnX)+e*d(lnZ

Postby cyp74 » Wed Jul 29, 2015 7:43 pm

A 1% increase in X will result in b% increase in Y.

startz
Non-normality and collinearity are NOT problems!
Posts: 3796
Joined: Wed Sep 17, 2008 2:25 pm

Re: Interpretation of coefficients: d(lnY)=c+b*(lnX)+e*d(lnZ

Postby startz » Wed Jul 29, 2015 7:59 pm

A 1% increase in X will result in b% increase in Y.
Not if the LHS variable is d(ln y)

SEbert
Posts: 6
Joined: Fri May 29, 2015 1:22 am

Re: Interpretation of coefficients: d(lnY)=c+b*(lnX)+e*d(lnZ

Postby SEbert » Sun Sep 13, 2015 9:19 am

If the LHS variable is d(ln y), what is the interpretation then? Thank you Admin.

startz
Non-normality and collinearity are NOT problems!
Posts: 3796
Joined: Wed Sep 17, 2008 2:25 pm

Re: Interpretation of coefficients: d(lnY)=c+b*(lnX)+e*d(lnZ

Postby startz » Sun Sep 13, 2015 10:13 am

The change in the rate of growth of y


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