Wald test

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bibimiwi
Posts: 35
Joined: Mon Apr 07, 2014 4:52 am

Wald test

Postby bibimiwi » Tue Apr 22, 2014 9:44 am

Hello,

I estimated a probit model with 7 explanatory variables of which 3 are dummy variables. Two of the explanatory variables are giving me a hard time: they have a z-statistic of -0.95 and 1.46 and p-values of 0.34 and 0.14. Therefore I concluded that they are not statistically signifcant. The Wald-test comes to the same result.
BUT if I run a reduntant variable test on those two explanatory variables, they are highly significant! (The correleation between those two variables is 0.82).
How can this be, that one time they are statistically significant and the other time not???

Thank you very much

EViews Glenn
EViews Developer
Posts: 2682
Joined: Wed Oct 15, 2008 9:17 am

Re: Wald test

Postby EViews Glenn » Tue Apr 22, 2014 10:19 am

What Wald test did you run?

startz
Non-normality and collinearity are NOT problems!
Posts: 3798
Joined: Wed Sep 17, 2008 2:25 pm

Re: Wald test

Postby startz » Tue Apr 22, 2014 10:25 am

It is very common for two coefficients to be jointly significant when neither is individually significant. Essentially, there is something common to the two variables that matters, but because the two variables are highly correlated it isn't possible to separate out which variable is responsible for the outcomes.

bibimiwi
Posts: 35
Joined: Mon Apr 07, 2014 4:52 am

Re: Wald test

Postby bibimiwi » Tue Apr 22, 2014 10:29 am

The one that eviews offers for the coefficient diagnostics (wald - Coefficient Restrictions...)

bibimiwi
Posts: 35
Joined: Mon Apr 07, 2014 4:52 am

Re: Wald test

Postby bibimiwi » Tue Apr 22, 2014 10:31 am

the thing is that I estimated various model, and all of them had those 2 variables included. And in all cases but this one, I was able to distinguish between those two variables.
Does a high correlation not only start at 0.98 and not already at 0.82?

EViews Glenn
EViews Developer
Posts: 2682
Joined: Wed Oct 15, 2008 9:17 am

Re: Wald test

Postby EViews Glenn » Tue Apr 22, 2014 11:22 am

On the Wald test...

Yes, but which hypothesis to test did you enter?

bibimiwi
Posts: 35
Joined: Mon Apr 07, 2014 4:52 am

Re: Wald test

Postby bibimiwi » Wed Apr 23, 2014 2:34 am

I am not sure if I understood your question...
I estimated a probit model.
Is this the answer to your question?

startz
Non-normality and collinearity are NOT problems!
Posts: 3798
Joined: Wed Sep 17, 2008 2:25 pm

Re: Wald test

Postby startz » Wed Apr 23, 2014 6:36 am

When you went to
The one that eviews offers for the coefficient diagnostics (wald - Coefficient Restrictions...)
what command did you enter?

bibimiwi
Posts: 35
Joined: Mon Apr 07, 2014 4:52 am

Re: Wald test

Postby bibimiwi » Wed Apr 23, 2014 10:20 am

the only way possible .. c(3), c(4).

I really think that I am not getting your question

startz
Non-normality and collinearity are NOT problems!
Posts: 3798
Joined: Wed Sep 17, 2008 2:25 pm

Re: Wald test

Postby startz » Wed Apr 23, 2014 10:25 am

the only way possible .. c(3), c(4).

I really think that I am not getting your question
Glenn asked for the command you entered. Did you type "c(3),c(4)"? Or did you type something different involving c(3) and c(4)?

bibimiwi
Posts: 35
Joined: Mon Apr 07, 2014 4:52 am

Re: Wald test

Postby bibimiwi » Wed Apr 23, 2014 10:26 am

only c(3),c(4)

startz
Non-normality and collinearity are NOT problems!
Posts: 3798
Joined: Wed Sep 17, 2008 2:25 pm

Re: Wald test

Postby startz » Wed Apr 23, 2014 11:05 am

When I do that on my version nothing happens. Equal signs are required as part of the specification.

bibimiwi
Posts: 35
Joined: Mon Apr 07, 2014 4:52 am

Re: Wald test

Postby bibimiwi » Wed Apr 23, 2014 11:16 am

Equal signs are required as part of the specification.
My coefficients indeed have different signs... do you think this is the problem??
Is it not possible to perform a wald test on two coefficients with different signs?

startz
Non-normality and collinearity are NOT problems!
Posts: 3798
Joined: Wed Sep 17, 2008 2:25 pm

Re: Wald test

Postby startz » Wed Apr 23, 2014 11:17 am

Equal signs are required as part of the specification.
My coefficients indeed have different signs... do you think this is the problem??
Is it not possible to perform a wald test on two coefficients with different signs?
By "equal signs" I meant literally "="

bibimiwi
Posts: 35
Joined: Mon Apr 07, 2014 4:52 am

Re: Wald test

Postby bibimiwi » Wed Apr 23, 2014 11:33 am

Oh I am so sorry! This was completely my fault!
Of course I mean C(3)=0 and C(4)=0


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