how do I retireve last date in current sample

[NurfatimaD]

Good day!

I am trying to rub a back testing for the follwing equation:

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equation cpi.ls log(cpic000/cpic000(-12)) log(mb30(-16)/mb30(-28)) log(lbwnm0000(-9)/lbwnm0000(-21)) log(p_faofoodi(-3)/p_faofoodi(-15)) log(mb30(-6)/mb30(-18))*log(lbwnm0000(-3)/lbwnm0000(-15))*log(p_faofoodi(-3)/p_faofoodi(-15))*log(p_brent/p_brent(-12))*log(cr_stock_total(-24)/cr_stock_total(-36)) log(p_kztusd/p_kztusd(-12)) c

the sample should increase from @first 2009:1 to @first @last. to do this i use the following code:

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%sampstart = "2008m12" 'start period of the back testing for !i=1 to 50 step 1 'repeat the analysis ending 97 periods ahead smpl @first {%sampstart}+!i

but now I need Eviews to retrieve the end date of the sample each time it iterates. Any thouhghts how to do this?

Thank you!

[EViews Gareth]

Something like:

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=@otod(@dtoo(%sampstart)+!i)

[NurfatimaD]

Something like:

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=@otod(@dtoo(%sampstart)+!i)

Thanks a lot! It really worked! :D