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Posted: **Wed Mar 26, 2014 9:49 am**

Hi

is it possible to use a string instead of manually writing down the model specification in and equation environment?`

Easy example, suppose this is the regression I want to run

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equation equ1.ls y c @movav(x1(0),3) x2

can I replace the model specification ie everything after "equ1.ls" with a string?
I have extracted the optimal model specification and lag structure for multitude of dependent variables, and the way it's set up is that the explanatory variables are enlisted in a string object. Most efficiently I would be able to incorporate this string into a loop, but I don't know if the equation environment lets me do so.

Easy example, let "_equ_y" be the string containing the optimal model specification eg.: "y c @movav(x1(0),3) x2"

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					for %bestvar {_equ_y}
						equation _equ1_y.ls %bestvar
						show equ1_y_				
					next

obviously only returns the alpha values in the string. Ideas?

Posted: **Wed Mar 26, 2014 9:55 am**

replace %bestvar with {%bestvar}

Posted: **Wed Mar 26, 2014 10:03 am**

Thanks Gareth, tried that before but gets me following error message:

"No coefficients specified in "euation equ1_y.ls y"

Posted: **Wed Mar 26, 2014 10:08 am**

try putting an extra set of braces. {{%bestvar}}

Posted: **Wed Mar 26, 2014 10:13 am**

That gives me following error message "y is not a valid string or scalar name in "Equation..." "

Interestingly it always only refers to the first varaible specfied in that string, which would explain why it cannot execute the regression.

Posted: **Wed Mar 26, 2014 10:23 am**

ok, I think we need more information on exactly what you're doing. The following program shows examples of how to do it in a variety of ways:

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create u 100
series y=nrnd
series x1=nrnd
series x2=nrnd

string _equ_y = "y c @movav(x1(0),3) x2"

equation eq1.ls {_equ_y}

%bestvar = _equ_y

equation eq2.ls {%bestvar}

%bestvar = "_equ_y"

equation eq3.ls {{%bestvar}}



   for %bestvar _equ_y
      equation _equ1_y.ls {{%bestvar}}     
   next

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