How do I create a dummy variable to correct for structural break within my data?
for example by looking at the resid graph shows a structural break in 1988 in my data
Data i have got given
c - constand
m
resid
r
y
kind regards
A
correct for structural break using dummy variable
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startz
- Non-normality and collinearity are NOT problems!
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Re: correct for structural break using dummy variable
series dummy = @year>1988
Re: correct for structural break using dummy variable
Thanks but when i do this, the coefficients change. aren't they meant to stay them same?
Kind regards
A.
Kind regards
A.
-
startz
- Non-normality and collinearity are NOT problems!
- Posts: 3798
- Joined: Wed Sep 17, 2008 2:25 pm
Re: correct for structural break using dummy variable
No, if the coefficients were going to stay the same what would you be correcting?Thanks but when i do this, the coefficients change. aren't they meant to stay them same?
Kind regards
A.
Re: correct for structural break using dummy variable
Oh thats true. thanks!
Also when use the dummy variable for lets say 1988
in my data for the dummy variable 1988 = 1 and all the rest of the dates are = to 0
but then if i in my data for the dummy variable 1988= 0 and the rest of the dates = 1
the coefficients are different from when 1988 = 1
which is correct?
Kind Regards
A.
Also when use the dummy variable for lets say 1988
in my data for the dummy variable 1988 = 1 and all the rest of the dates are = to 0
but then if i in my data for the dummy variable 1988= 0 and the rest of the dates = 1
the coefficients are different from when 1988 = 1
which is correct?
Kind Regards
A.
-
startz
- Non-normality and collinearity are NOT problems!
- Posts: 3798
- Joined: Wed Sep 17, 2008 2:25 pm
Re: correct for structural break using dummy variable
Only the constant should have changed.
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