Is "ls y c y(-1)" and "ls y c ar(1)" the same?
Posted: Sun May 15, 2011 8:49 am
hi,
when i constract model AR(1), i find that
ls y c y(-1)
and
ls y c ar(1)
has different result,
I want to know which one is the real AR(1) model----y=c+b*y(-1)?
Thanks!
when i constract model AR(1), i find that
ls y c y(-1)
and
ls y c ar(1)
has different result,
I want to know which one is the real AR(1) model----y=c+b*y(-1)?
Thanks!