Hi!
I am still a beginner with Unit root tests in EViews, and I need urgent help concerning the following output:
KPSS Test Level Intercept
Null Hypothesis: BN_LOG is stationary
Exogenous: Constant
Bandwidth: 18 (Newey-West using Bartlett kernel)
Kwiatkowski-Phillips-Schmidt-Shin test statistic 1.905745
Asymptotic critical values*: 1% level 0.739000
5% level 0.463000
10% level 0.347000
Residual variance (no correction) 0.087861
HAC corrected variance (Bartlett kernel) 1.581625
KPSS Test Equation
Dependent Variable: BN_LOG
Method: Least Squares
Date: 06/09/10 Time: 12:00
Sample: 2/26/2008 3/31/2010
Included observations: 534
Coefficient Std. Error t-Statistic Prob.
C 7.383234 0.012839 575.0586 0.0000
R-squared 0.000000 Mean dependent var 7.383234
Adjusted R-squared 0.000000 S.D. dependent var 0.296692
S.E. of regression 0.296692 Akaike info criterion 0.409624
Sum squared resid 46.91779 Schwarz criterion 0.417639
Log likelihood -108.3695 Hannan-Quinn criter. 0.412760
Durbin-Watson stat 0.008087
This is the output I get for testing in level and with intercept...does this mean that my series are stationary???
Thx in advance for your help!!!
KPSS Test Output Interpretation
Moderators: EViews Gareth, EViews Moderator
Re: KPSS Test Output Interpretation
Hi - According to the test result, the time series has no unit root (you cannot reject the null hypothesis).
Re: KPSS Test Output Interpretation
Hi again - I must have mistakenly looked on a different number because the test result shows that the null hypothesis is rejected: So the time series has proably a unit root and is NOT stationary - sorry about the confusion.
Re: KPSS Test Output Interpretation
To refer back to the interpretation question.
The important value is the Kwiatkowski-Phillips-Schmidt-Shin test statistic, in this case 1.905745 to decide wether to reject or not. AM I right here in this assumption?
The important value is the Kwiatkowski-Phillips-Schmidt-Shin test statistic, in this case 1.905745 to decide wether to reject or not. AM I right here in this assumption?
Re: KPSS Test Output Interpretation
Hi, yes, that's correct.To refer back to the interpretation question.
The important value is the Kwiatkowski-Phillips-Schmidt-Shin test statistic, in this case 1.905745 to decide wether to reject or not. AM I right here in this assumption?
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zahideconomist
- Posts: 3
- Joined: Thu May 08, 2014 12:04 pm
Re: KPSS Test Output Interpretation
Hi
I need urgent help concerning the following output is Variable Y is stationary or not?
Null Hypothesis: Y is stationary
Exogenous: Constant, Linear Trend
Bandwidth: 4 (Newey-West automatic) using Bartlett kernel
LM-Stat.
Kwiatkowski-Phillips-Schmidt-Shin test statistic 0.211095
Asymptotic critical values*: 1% level 0.216000
5% level 0.146000
10% level 0.119000
*Kwiatkowski-Phillips-Schmidt-Shin (1992, Table 1)
Residual variance (no correction) 36006.27
HAC corrected variance (Bartlett kernel) 114183.4
KPSS Test Equation
Dependent Variable: Y
Method: Least Squares
Date: 05/17/14 Time: 22:12
Sample: 1971 2011
Included observations: 41
Variable Coefficient Std. Error t-Statistic Prob.
C 876.0881 59.67462 14.68108 0.0000
@TREND("1971") 9.145404 2.567987 3.561313 0.0010
R-squared 0.245399 Mean dependent var 1058.996
Adjusted R-squared 0.226050 S.D. dependent var 221.1528
S.E. of regression 194.5578 Akaike info criterion 13.42689
Sum squared resid 1476257. Schwarz criterion 13.51048
Log likelihood -273.2512 Hannan-Quinn criter. 13.45732
F-statistic 12.68295 Durbin-Watson stat 0.271097
Prob(F-statistic) 0.000991
I need urgent help concerning the following output is Variable Y is stationary or not?
Null Hypothesis: Y is stationary
Exogenous: Constant, Linear Trend
Bandwidth: 4 (Newey-West automatic) using Bartlett kernel
LM-Stat.
Kwiatkowski-Phillips-Schmidt-Shin test statistic 0.211095
Asymptotic critical values*: 1% level 0.216000
5% level 0.146000
10% level 0.119000
*Kwiatkowski-Phillips-Schmidt-Shin (1992, Table 1)
Residual variance (no correction) 36006.27
HAC corrected variance (Bartlett kernel) 114183.4
KPSS Test Equation
Dependent Variable: Y
Method: Least Squares
Date: 05/17/14 Time: 22:12
Sample: 1971 2011
Included observations: 41
Variable Coefficient Std. Error t-Statistic Prob.
C 876.0881 59.67462 14.68108 0.0000
@TREND("1971") 9.145404 2.567987 3.561313 0.0010
R-squared 0.245399 Mean dependent var 1058.996
Adjusted R-squared 0.226050 S.D. dependent var 221.1528
S.E. of regression 194.5578 Akaike info criterion 13.42689
Sum squared resid 1476257. Schwarz criterion 13.51048
Log likelihood -273.2512 Hannan-Quinn criter. 13.45732
F-statistic 12.68295 Durbin-Watson stat 0.271097
Prob(F-statistic) 0.000991
Re: KPSS Test Output Interpretation
According to the results the null-hypothesis is rejected, which indicates non-stationarity. The data seem to have a deterministic trend as well. Eliminate the deterministic trend and test the null-hypothesis again.
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zahideconomist
- Posts: 3
- Joined: Thu May 08, 2014 12:04 pm
Re: KPSS Test Output Interpretation
hi
thanks for comments now my results are:
Null Hypothesis: D(LY) is stationary
Exogenous: Constant, Linear Trend
Bandwidth: 7 (Newey-West automatic) using Bartlett kernel
LM-Stat.
Kwiatkowski-Phillips-Schmidt-Shin test statistic 0.092292
Asymptotic critical values*: 1% level 0.216000
5% level 0.146000
10% level 0.119000
*Kwiatkowski-Phillips-Schmidt-Shin (1992, Table 1)
Residual variance (no correction) 0.007112
HAC corrected variance (Bartlett kernel) 0.002123
KPSS Test Equation
Dependent Variable: D(LY)
Method: Least Squares
Date: 05/31/14 Time: 10:12
Sample (adjusted): 1972 2011
Included observations: 40 after adjustments
Variable Coefficient Std. Error t-Statistic Prob.
C -0.044376 0.027883 -1.591500 0.1198
@TREND("1971") 0.002582 0.001185 2.178300 0.0357
R-squared 0.111007 Mean dependent var 0.008548
Adjusted R-squared 0.087612 S.D. dependent var 0.090585
S.E. of regression 0.086526 Akaike info criterion -2.008038
Sum squared resid 0.284496 Schwarz criterion -1.923594
Log likelihood 42.16076 Hannan-Quinn criter. -1.977506
F-statistic 4.744992 Durbin-Watson stat 2.332809
Prob(F-statistic) 0.035657
Please comment
thanks for comments now my results are:
Null Hypothesis: D(LY) is stationary
Exogenous: Constant, Linear Trend
Bandwidth: 7 (Newey-West automatic) using Bartlett kernel
LM-Stat.
Kwiatkowski-Phillips-Schmidt-Shin test statistic 0.092292
Asymptotic critical values*: 1% level 0.216000
5% level 0.146000
10% level 0.119000
*Kwiatkowski-Phillips-Schmidt-Shin (1992, Table 1)
Residual variance (no correction) 0.007112
HAC corrected variance (Bartlett kernel) 0.002123
KPSS Test Equation
Dependent Variable: D(LY)
Method: Least Squares
Date: 05/31/14 Time: 10:12
Sample (adjusted): 1972 2011
Included observations: 40 after adjustments
Variable Coefficient Std. Error t-Statistic Prob.
C -0.044376 0.027883 -1.591500 0.1198
@TREND("1971") 0.002582 0.001185 2.178300 0.0357
R-squared 0.111007 Mean dependent var 0.008548
Adjusted R-squared 0.087612 S.D. dependent var 0.090585
S.E. of regression 0.086526 Akaike info criterion -2.008038
Sum squared resid 0.284496 Schwarz criterion -1.923594
Log likelihood 42.16076 Hannan-Quinn criter. -1.977506
F-statistic 4.744992 Durbin-Watson stat 2.332809
Prob(F-statistic) 0.035657
Please comment
Re: KPSS Test Output Interpretation
According to your results the null hypothesis cannot be rejected. The transformed variable is level stationary.
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Re: KPSS Test Output Interpretation
So in summary we can say if
Kwiatkowski-Phillips-Schmidt-Shin test statistic Value is less than (<) any of the below than we would accept the null i.e the variable is stationary.
Asymptotic critical values*: 1% level 0.216000
5% level 0.146000
10% level 0.119000
Please answer.
Kwiatkowski-Phillips-Schmidt-Shin test statistic Value is less than (<) any of the below than we would accept the null i.e the variable is stationary.
Asymptotic critical values*: 1% level 0.216000
5% level 0.146000
10% level 0.119000
Please answer.
Re: KPSS Test Output Interpretation
if the estimated test statistic is less than the critical values tabulated above, yes, you fail to reject the null of stationarity.So in summary we can say if
Kwiatkowski-Phillips-Schmidt-Shin test statistic Value is less than (<) any of the below than we would accept the null i.e the variable is stationary.
Asymptotic critical values*: 1% level 0.216000
5% level 0.146000
10% level 0.119000
Please answer.
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