hi,
when i constract model AR(1), i find that
ls y c y(-1)
and
ls y c ar(1)
has different result,
I want to know which one is the real AR(1) model----y=c+b*y(-1)?
Thanks!
Is "ls y c y(-1)" and "ls y c ar(1)" the same?
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startz
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Re: Is "ls y c y(-1)" and "ls y c ar(1)" the same?
They are the same except for the interpretation of the constant.
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EViews Gareth
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