The percentile of the median is 50. This means that if the median of a
distribution were 66, then 50 percent of the observations are 66 and below.
However, the percentile of the mean value is not readily known. To ask,
suppose the mean of a distribution were 74, what is the equivalent
percentile? Could someone help with the syntax to calculate the percentile
of the mean?
Dr Avwokeni
Percentile of the Mean
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Re: Percentile of the Mean
Obvious, if not slick, method is simply:
Code: Select all
smpl if x<=@mean(x)
scalar mypercentile = @obssmpl/@obsrange*100
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Re: Percentile of the Mean
It works, but not so obvious as you remarked. Many thanks
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