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Ah I got it sorry. I forgot to put !n instead of 1 for the columns in the second loop:

matrix x=@ones(101, 77)
For !n=1 to @columns(x)
For !m=2 to @rows(x)
x(!m,!n)=x(!m-1,!n)*(1-deathprob_1yr(!m-1,!n))
next
next

Thanks again Gareth

Thanks Gareth that works very well. I just had to fill x with ones first, otherwise the vector fills with zeros. Regarding the greater loop, i turned x into a matrix and did as you said and every other column just filled with ones. The code is: matrix x=@ones(101, 77) For !n=1 to @columns(x) For !m=...

Hi, I have another coding issue. I would like to fill a matrix using a for loop so that each cell in a column is equal to the value of the cell above it multiplied by (1 - the value of the cell above the corresponding cell in another matrix). Therefore, using microsoft excel to demonstrate, B2 = B1*...

Thankyou, worked a treat.

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