Search found 8 matches
- Mon Jun 26, 2017 11:54 pm
- Forum: Programming
- Topic: Extracting results from tables
- Replies: 4
- Views: 4468
Re: Extracting results from tables
Thanks!!
- Mon Jun 26, 2017 4:40 pm
- Forum: Programming
- Topic: Extracting results from tables
- Replies: 4
- Views: 4468
Re: Extracting results from tables
Thanks, solution found! !resettest=4 !size=@obs(complete) !regressions=@obs(complete) for !y= 1 to !regressions !x=complete(!y) 'Ramsey RESET for !a=1 to !resettest freeze(rtable) temp{!x}.reset(!a) for !e=7 to 12 !xx2=@isna(@val(rtable(!e,4))) if !xx2=0 then exitloop endif next vector (!y) rt{!a} r...
- Mon Jun 26, 2017 8:56 am
- Forum: Programming
- Topic: Extracting results from tables
- Replies: 4
- Views: 4468
Extracting results from tables
Hi, I am having a problem with extracting the results from tables (in particular RESET test). I am using stepls in a loop and as expected each regression has a different number of independent variables. The problem is that the row number in the frozen table containing the statistic (or the p-value) ...
- Thu Jun 15, 2017 10:40 pm
- Forum: Programming
- Topic: ubreak for a single regressor
- Replies: 8
- Views: 5969
Re: ubreak for a single regressor
Many thanks. I have a doubt about what is assumed in the multibreak; The multibreak (Bai Perron) is for a disjoint trend, right? The trend is not joined at the breakpoint (it assumes a jump as opposed to the Perron-Yabu, for example). In this way, the multibreak (maxbreaks=1) is not a close replacem...
- Thu Jun 15, 2017 10:23 pm
- Forum: Programming
- Topic: ubreak for a single regressor
- Replies: 8
- Views: 5969
Re: ubreak for a single regressor
Dear Gareth,
Many thanks. Do you have an idea about when this bug will be fixed?
Best regards,
Francisco
Many thanks. Do you have an idea about when this bug will be fixed?
Best regards,
Francisco
- Thu Jun 15, 2017 8:01 am
- Forum: Programming
- Topic: ubreak for a single regressor
- Replies: 8
- Views: 5969
Re: ubreak for a single regressor
Dear Gareth, Here is a simple example of the problem with this function. Please tell me if I am doing something wrong or if it is a bug (and hopefully if there is a way to solve it): genr x=nrnd genr y=nrnd equation eq1.ls y c @trend x freeze(qa) eq1.ubreak 15 @ @trend As you can see if you run the ...
- Thu Jun 15, 2017 7:50 am
- Forum: Programming
- Topic: ubreak for a single regressor
- Replies: 8
- Views: 5969
Re: ubreak for a single regressor
But it does not... the results you get are not for @trend but for all the variables in your regression. I really need the results only for one of the variables, not for all of them. I am using Eviews 9.5 version. Is this a known bug? Is there a way to get results for only one variable in a program? ...
- Wed Jun 14, 2017 7:33 pm
- Forum: Programming
- Topic: ubreak for a single regressor
- Replies: 8
- Views: 5969
ubreak for a single regressor
Hi, I am trying to test for a break in one of the independent variables in several ols regressions. However, the tests results that I get are for all equation variables (i.e., Varying regressors: All equation variables) and not only for the variable I want. Please help. The relevant part of the code...
