Thanks for your comments.Just to clarify, isn't your hypothesis linear?
(I-A) = A -> I = 2*A -> I/2 = A
Indeed it's linear..
But what if the matrix is too complicated to compute, like (I-A)^10=A ?
Thanks for your comments.Just to clarify, isn't your hypothesis linear?
(I-A) = A -> I = 2*A -> I/2 = A