Hello, I'm trying to run this, I mean I want to generate hdebt_10, hdebt_10.5, hdebt_11 up to hdebt_12, the same for ldebt. But Eviews can´t generate hdebt_10.5, I do not why. It shows a message like this "5 is not a member or procedure of hdebt_10 in "series hdebt_!x"=1" How I can compute the series with decimals?
for !x=10 to 12 step 0.5
smpl if debt>!x
series hdebt_!x=1
smpl @all
smpl if debt<!x
series ldebt_!x=1
smpl @all
call regressions
next
Thanks for your help!
Loop with decimals
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- Fe ddaethom, fe welon, fe amcangyfrifon
- Posts: 13309
- Joined: Tue Sep 16, 2008 5:38 pm
Re: Loop with decimals
I'm trying to run this to generate hdebt_105=1 when debt>10.5... because I can't generate hdebt_10.5 because of the point bu it doesn't work. How I could do this?
for !x=10 to 12 step 0.5
smpl if debt>!x
for !i=100 to 120 step 5
series hdebt_!i=1
smpl @all
for !x=10 to 12 step 0.5
smpl if debt<!x
for !i=100 to 120 step 5
series ldebt_!i=1
smpl @all
string grps = "hdebt_!i ldebt_!i"
call regressions
next
next
next
next
for !x=10 to 12 step 0.5
smpl if debt>!x
for !i=100 to 120 step 5
series hdebt_!i=1
smpl @all
for !x=10 to 12 step 0.5
smpl if debt<!x
for !i=100 to 120 step 5
series ldebt_!i=1
smpl @all
string grps = "hdebt_!i ldebt_!i"
call regressions
next
next
next
next
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- EViews Developer
- Posts: 560
- Joined: Thu Apr 25, 2013 7:48 pm
Re: Loop with decimals
Hello,
You can create a string version of the number and then use @replace to remove the ".", e.g., @replace(@str(!x), ".", "").
You can create a string version of the number and then use @replace to remove the ".", e.g., @replace(@str(!x), ".", "").
-
- Fe ddaethom, fe welon, fe amcangyfrifon
- Posts: 13309
- Joined: Tue Sep 16, 2008 5:38 pm
Re: Loop with decimals
I have tried to run it like this, it could work?
for !x=10 to 12 step 0.5
!i=!x*10
smpl if debt>!x
series hdebt_!i=1
smpl @all
smpl if debt<!x
series ldebt_!i=1
smpl @all
next
for !x=10 to 12 step 0.5
!i=!x*10
smpl if debt>!x
series hdebt_!i=1
smpl @all
smpl if debt<!x
series ldebt_!i=1
smpl @all
next
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- EViews Developer
- Posts: 560
- Joined: Thu Apr 25, 2013 7:48 pm
Re: Loop with decimals
Sure, go ahead and run it to find out.
Re: Loop with decimals
Ok, it doesn't, it generates hdebt_100 but then a message window error shows that it hadn't find " hdebt_1001". I don't know why from hdebt_100 it goes to hdebt_1001.
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- EViews Developer
- Posts: 560
- Joined: Thu Apr 25, 2013 7:48 pm
Re: Loop with decimals
Did you accidentally type "hdebt_!i1" somewhere in your code?
Re: Loop with decimals
No, there is no a 1. It is weird, however if I want to use what you said, the code @replace to have hdebt_105 instead of hdebt_10.5 that is not possible, where I have to put this code @replace(@str(!x), ".", "") ? Thank you very much for your help.
for !x=10 to 12 step 0.5
smpl if debt>!x
series hdebt_!x=1
smpl @all
smpl if debt<!x
series ldebt_!x=1
smpl @all
next
for !x=10 to 12 step 0.5
smpl if debt>!x
series hdebt_!x=1
smpl @all
smpl if debt<!x
series ldebt_!x=1
smpl @all
next
-
- EViews Developer
- Posts: 560
- Joined: Thu Apr 25, 2013 7:48 pm
Re: Loop with decimals
Creating a string to hold the result of that expression will work, e.g.,
Code: Select all
string tmp = @replace(@str(!x), ".", "")
series hdebt_{tmp}=1
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