Hello,
I have this (below) and I want to construct scalar "f" with the scalar "deuda" that in numercis value is 73. But it does not work because when I try to construct scalar f it, Eviews doesnt'read "ssrt_deuda" which in fact is "ssrt_73" that I have previously compute in the program. How I can do this?
scalar min=@imin(a2) = 64
scalar deuda= min+9= 73
scalar f= (5.031087- ssrt_deuda ) / ssrt_deuda = (5.031087- ssrt_73 ) / ssrt_73
Thanks,
Luciana
Use a scalar in a series name
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Re: Use a scalar in a series name
Hello,
Use variable replacement with {}'s. For example,
Use variable replacement with {}'s. For example,
Code: Select all
scalar f= (5.031087- ssrt_{deuda} ) / ssrt_{deuda} = (5.031087- ssrt_73 ) / ssrt_73
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