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Hi, So how do I find the residual results for the ECM/ARDL? Bth the original ARDL and the parsimonious ECM/ARDL use the same seated mod, so I'm guessing they have the same residual result??? The residuals from the contemporaneous and the ECM model are identical. All inferences on the residuals gene...

I suggest you start by reading our blog series on ARDL estimation. Here are the links: http://blog.eviews.com/2017/04/autoregressive-distributed-lag-ardl.html?m=1 http://blog.eviews.com/2017/05/autoregressive-distributed-lag-ardl_8.html?m=1 http://blog.eviews.com/2017/05/autoregressive-distributed-l...

Yes. The Johansen test is done on the VECM representation.

Why do you need peer-reviewed journals to show this? You can do so yourself directly. It's pretty rudimentary. I'll give you the case for p = 1 and p = 2. You can use mathematical induction or a brute force method to demonstrate the general case. VAR(1) => Y_t = Gamma * Y_{t-1} + Beta * X + eps_t = ...

Hi! The reason that you don't see the constant or trend terms in the long-run levels equation is due to the fact that you are estimating ARDL using the deterministic scheme 5 which does not subject the constant and the trend to the long-run restriction. In other words, the constant and trend are NOT...

Ah! I think I understand your point now. What you are claiming is "incorrect" is in fact the Error Correction Form (ECM) of the ARDL model. And you are right! The ECM is NOT equal to the cointegrating equation that we display in the outputs we have pasted earlier, namely. Cointegrating Equ...

Hi Jamel, I'm not entirely sure how you're obtaining that output, but when I run the estimation on my end, the output I receive is: ---------- Estimation Command: ========================= ARDL @FL(REALCONS,1) @FL(REALGDP,1) @ Estimation Equation: ========================= REALCONS = C(1)*REALCONS(-...

Hi! At the moment we've chosen to only support HEGY, Likelihood HEGY, Canova-Hansen, and the Variance Ratio seasonal unit root tests. Following Ghysels, Lee, and Noh (1994) we've decided against initial support for the DHF test. This is by no means a permanent decision and we may in fact decide to s...

What form of the ECM were you expecting? Theoretically transforming the ARDL equation to an ECM equation results in the form you are seeing in the EViews output. I suggest you take a look at our 3-part blog series on ARDL estimation to understand why this is the case. This conversion from the ARDL e...

Can you please provide a copy of your workfile and/or some screenshots for context?

To determine if residuals are serially correlated, you must use tests designed to test for this specifically. The most famous of these tests is the Durbin-Watson, but you should probably use the LM tests proposed by White, Breusch-Pagan-Godfrey, Harvey, and so on. Note that if you are testing for un...

Because the variables which are missing from the ECM regression were most likely estimated as having 0 lag. In this case, they would be captured by the CointEq(-1) term entirely and would not have transitory effects (differences) as the other variables do.

The differencing that happens is a byproduct of the theoretical construction. In other words, even if you create a variable series z = x-x(-4) and use said series to specify your VECM, you will find that your transitory portion of the VECM will be specified in terms of lagged differences D(z) = z-z(...

If I understand your question correctly, you are wondering about the alpha*beta' partialization of the cointegrating matrix? If this indeed the case, then the answer is no since alpha*beta' = -0.402196 for this co-integrating relationship. In other words,-1.217436 is an element of beta, which is the...

Indeed. In fact, if you go to View and then Representations, and search among that output, you'll see that the VEC equation for your co-integrating relationship is in fact: D(LPE)=-0.402196*(LPE(-1)-1.217436*LPG(-1)-0.206260*LPS(-1)+1.193296)+0.442810*D(LPE(-1))-0.267557*D(LPG(-1)) ... etc