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3-Great! 4-generate multi series differenced lag: n1=represent the first number (order) that the series to be laged, and n2=the last suppose i would to have 4 series diff lag, i will put @dlag(x,1,4) this function will generate four series diff lag d(@lag(x,1)),....,d(@lag(x,4)). now suppose i would...

Hi everybody 1) could you add a button "resample= @all " beside sample in the workfile to make easy to resample the data when i use "smpl date1 date2". 2) make "select all" when i clic in the right mouse, to select all proram (i can use CTRL+A). 3) make restore button o...

exactlly what that i need, i learned many things from you Mr Gareth many thanks!
(**) EViews 9 Command Ref, chap 11, pp 264-265
matrix xsub = x.@row(@fill(1, 3, 4))
extracts the first, third, and fourth rows of the matrix X into the matrix XSIB. XSIB should be xsub.

thanks!
can you help me to simplify the code by "if", it's just to understand the methodologie of the loop by if.

1-sorry, is another question :oops: ok!, how can combined vector to the matrix by function? 2-vector v1 = @vec(m1), extract column to the vector, but how can extract by row to the vector, i have used @rows but it not work. 3- it's solved but can i use if to simplify by "if" matrix(4,3) m e...

1)i would just place the four coefs of factors "c(3), c(4), c(5), c(6)" in the first column, and "c(7), c(8), c(9), c(10)" in the second column, ...etc
2) can i combined three vector(3) in the matrix(3,3) by function?

by this code i get one value of factors in m(1,1) but all others values are constant matrix(4,3) m equation eq eq.ls y y(-1) y(-2) @expand(@month) for !i=1 to 4 for !j=1 to 3 for !k= 3 to 12 if !i>=1 and !j=1 and !k=!i+2 then m(!i,!j)=eq.@coef(!k) if !i>=1 and !j=2 and !k=!i+6 then m(!i,!j)=eq.@coef...

it work, thanks!. i use this code but a get a constant value in the matrix: matrix(4,3) m equation eq eq.ls y y(-1) y(-2) @expand(@month) for !i=1 to 4 for !j=1 to 3 !k=m(!i,!j) m(!i,!j)=eq.@coef(!k) next next i would just put the factors coefs by column in the matrix. (*) there is a tini mistake in...

Hi everybody this code extract coefs factors in the vectors but i get a constant value in the vectors 0.605271, I have a fault somewhere :roll: vector(12) v equation eq eq.ls y y(-1) y(-2) @expand(@month) for !i= 1 to 12 for !j=3 to 14 v(!i)=eq.@coef(!j) next next any help!

thanks alot! Mr Gareth, Your help was very useful.
i'm really enjoyed! with this software.

you understood me Mr Gareth.
I would highly appreciate if you could help me!

1st code: series t = @recode(@during("1990m1 1997m6") or @during("2000m1 2002m12"), @trend+1, 0) smpl 2000m1 2002m12 series t=t-120 smpl @all in my simple case i can use smpl no problem, but suppose if i have multi period to make trend i will always make smpl date1 date2, series...

1st code: when i substruct 119 from period "1990m1 1997m6" trend will be this -119 -118 -197....-30. from period "2000m1 2002m12" the code work. trend take 1 2 3....36. series t = @recode(@during("1990m1 1997m6") or @during("2000m1 2002m12"), @trend-119, 0) b...

this code generate trend for period 1990m1 1997m6 (trend take 0 1 2 3.....89), but from 2000m1 2002m12 it take this value 120 121 122.....155. i would like this: from 1990m1 1997m6 take 1 2 3 4.... from 2000m1 2002m12 take 1 2 3 4.... other period take 0 series t = @recode(@during("1990m1 1997m...

another question
generate trend:
the 1st year take trend
the 2nd year take 0
the 3rd year take trend
the 4th take 0.....and so on.